Given a
Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+For example, return the following Ids for the above Weather table:
+----+ | Id | +----+ | 2 | | 4 | +----+
Solution:
SELECT w1.Id FROM Weather as w1 inner join Weather as w2 ON TO_DAYS(w1.DATE) = TO_DAYS(w2.DATE) + 1 AND w1.Temperature > w2.Temperature
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